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National Certificate in Civil Engineering Year 2 Structural Mechanics During our time in structural mechanics the class as a whole was given a Program Integrated Assessment (PIA), which was to calculate a floor plan, showing beam loading (refer to Introduction on start sheet). The following diagrams and calculations are the result of calculating the floor beam. From Floor Plan, showing beam loading we can concluded that: - Beams 1(A) and 1(B) have a free body diagram of: - Beams 2(A) and 2(B) have a free body diagram of: - Beams 3(A), 3(B), 3(C) and 3(D) have a free body diagram of: - Calculating Beams: - 1(A) and 1(B) Taking moments about A to calculate V2. ?M = 0 or ?clockwise moments = ?anti-clockwise moments. 10 x 5 x 2.5 - 5V2 = 0 10 x 5 x 2.5 = 5V2 5V2 = 125 Hence V2 = 125/5 = 25KN Resolving Vertically to find the vertical reaction V1 ?V = 0 or ?forces upwards = ?forces downwards V1 + V2 =...

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