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Triangles "Two students are discussing how to find the biggest value of the area: perimeter ratio for triangles. One of them suggests that this can be done with measurements of 40, 60 and 80 but forgets to say what units were used and whether they were angles or sides. Which triangle gives the biggest area: perimeter ratio? Investigate further." To investigate this problem I am going to find out all the different combinations of triangles with the measurements of 40, 60 and 80. Then work out their area: perimeter ratio. From this I hope to make a valid conclusion. 1) If 40, 60 and 80 are all sides; Therefore the perimeter = 40+60+80=180 And the area, which can be worked out using the formula: 1/2absinC = 0.5x40x80xsin47 = 1170.16...** So the area: perimeter ratio = 1170.16... / 180 = 6.5 (1dp) 2) If 40, 60 and 80 are all angles; 3) If there are 2 angles and 1 side; This...

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