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The Koch Snowflake - Portfolio SL Type I Stage 0 Stage 1 Stage 2 Stage 3 Stage 4 1. Using an initial side length of 1, the table below was created to show the values of Nn, ln, Pn, and An for n=0, 1, 2 and 3. n Nn Ln Pn An 0 3 1 3 0.433 1 12 1/3 4 0.577 2 48 1/9 5.33 0.642 3 192 1/27 7.11 0.670 It can be seen that each successive terms of values for Nn are multiplied by 4 : - 3x4=12, 12x4 =48, 48x4=192 , etc; The relationship between each values of Ln is that each of these are multiplied by 1/3 to equal the successive value :- 1x1/3 = 1/3, 1/3 x 1/3 = 1/9, 1/9 x 1/3 = 1/27 , etc; The perimeter was found by multiplying the Number of sides with the length of the sides and there is no evident relationship between the values of perimeter. The area was found by calculating the triangles added to the main triangle and then adding that to the area of the main...

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