Logged out
Access All our Essays in an Instant
Swap your work for FREE access, or pay £4.99 for instant access
The Fencing Problem
Member rating:
(1 vote)
| Words:
| Submitted: Thu Jul 11 2002
Page Preview
On the left is an image preview of every page of this document, and below are the first 150 words with formatting removed:
The Fencing Problem For the first part of my investigation, I will have to some possible figures for the plot of land, making sure that the perimeter is 1000m. For my first examination, I will start with quadrilaterals. Side 1: 100m Side 2: 400m Side 1: 200m Side 2: 300m Side 1: 250m Side 2: 250m Side 1: 450m Side2: 50m Side 1: 350m Side2: 150m Side 1 Side 2 Area 100 m 400 m Side*side= 40000 m2 250 m 250 m Side*side= 62500 m2 300 m 200 m Side*side= 60000 m2 350 m 150 m Side*side= 52500 m2 450 m 50 m Side*side= 22500 m2 The graph and the table indicate that when the width and the height of a regular quadrilateral have the least difference, the Area is at its greatest. This statement is proven by the square. A square has all the sides the same, so the difference is at the smallest since it is at zero. The Area of the square is the greatest, and this leads me to believe that regular shapes- i.e....
Get instant access
- Instant, unlimited access to our documents in full
- Swap your work for free access, or pay £4.99
- To see the full version of this document and 147,195 others
Receive email updates for this category
- Simply tell us your email address and receive a weekly Study Help Email for FREE
- Receive 3 FREE essay views with each email
- Get all the latest essays from Coursework.Info & discussion from TheStudentRoom.co.uk
