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The Fencing Problem
- Words:
- 815
- Submitted:
- Thu Oct 07 2004

Have a little read: ... I am investigating a problem to do with a plot of land with either a perimeter or a circumference of 1000 m. There are many possibilities for the she farmer to plot her fence round the area of land. She can plot in triangles, hexagons, decagons, rectangles, squares etc. First, I am going to try to find out the greatest area for a rectangle. If I try using a rectangle with length of 400 m, and a width of 100 m, I am going to find out its area. Here, I have a rectangle of width w, which must have a length of 500 - w, if the perimeter is to 1000 m. CHECK: W + 500 - w + 500 - w + 500 - w. = 500 w - w2 A = 500 w - w 2 Its area is w (500 - w) A = 500w - w2 If I multiply the length (400
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