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I have been asked to find out the isoperimetric quotients of plane shapes using the formula: I.Q = 4ð x area of shape  

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Maths Coursework: Isoperimetric Quotients I have been asked to find out the isoperimetric quotients of plane shapes using the formula: I.Q = 4? x area of shape (Perimeter of shape)2 I will use the answers to find a pattern between the I.Qs of plane shapes. I will start with a circle as it only has one side, and then try other shapes increasing the number of sides each time. To help me find a pattern I will make a table of results containing both the answers with ? in it, and the answer worked out to a number to 2 decimal places. I.Q = 4? x area of shape (Perimeter of shape) ² = 4? x ?r² (? d) ² = 4? x 12.566370614359172953850573533118 157.91367041742973790135185599802 = 157.91367041742973790135185599792 157.91367041742973790135185599792 I.Q = 1 I.Q = 4? x ?r² (?d) ² = 4? x 113.09733552923255658465516179806 1421.2230337568676411121667039822 = 1421.2230337568676411121667039814 1421.2230337568676411121667039814 I.Q = 1 After trying the I.Q formula on 2 different...

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