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Beyond Pythagoras For this piece of coursework I am trying to find Pythagorean triplets (these are whole numbers that's satisfies Pythagoras theorem). Pythagoras Theorem is a2 + b2 = c2. (a) being the shortest side, (b) being the middle side and (c) being the longest side (hypotenuse) of a right angled triangle. The numbers 3, 4 and 5 satisfy this condition 32 + 42 = 52 because 32 = 3 x 3 = 9 42 = 4 x 4 = 16 52 = 5 x 5 = 25 = 32 + 42 = 9 + 16 = 25 = 52 To find the perimeter we add all the sides together. Perimeter = 3 + 4 + 5 = 12 Finally to find the areas we times the smallest and middle side and then divide by to. Area = 1/2 x 3 x 4 = 6 I will now put the first term in to a table...

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