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Beyond Pythagoras
Member rating: No Rating | Words: | Submitted: Fri Nov 05 2004
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TO: Mr. Fray FROM: Nadia Falcon (12 - GH) DATE: 11th March, 2002 TITLE: Beyond Pythagoras 1. INTRODUCTION: ( In this coursework I am required to find out the area and perimeter of the following sets of numbers 3,4,5; 5,12,13 and 7,24,25 of right angle triangles and whether they satisfy a similar condition by using the formula of the Pythagoras Theorem, which is, (shortest side) ² + (middle side) ² = (longest side) ² 2. PROCEDURE: ( I am going to work out the area and perimeter of the following three triangles with measurements, 3,4,5; 5,12,13 and 7,24,25 to check if they satisfy the condition (Shortest side) ² + (Middle side) ² = (Longest side) ² of the Pythagoras Theorem. 1) The numbers 3,4,5 satisfy this condition because - 3² + 4² = 5² So shortest side 3² = 3 x 3 = 9 Middle side 4² = 4 x 4 = + 16 -------- 25 And Longest side 5² = 5 x...
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