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- Words:
- 2107
- Submitted:
- Mon Oct 06 2003
... Mathematics Coursework - Beyond Pythagoras Mathematics Coursework BEYOND PYTHAGORAS By Asif Azam 1) The numbers 3, 4, and 5 satisfy the condition 3² + 4² = 5² because 3² = 3x3 =9 4² = 4x4 = 16 5² = 5x5 = 25 and so 3² + 4² = 9 + 16 = 25 = 5² I will now have to find out if the following sets of numbers satisfy a similar condition of (smallest number) ² + (middle number) ² = (largest number) ². a) 5, 12, 13 5² + 12² = 25 + 144 = 169 = 13² b) 7, 24, 25 7² + 24² = 49 + 576 = 625 = 25² 2) Perimeter 5 5 + 12 + 13 = 20 12 studentcentral.co.uk 7 7 + 24 + 25 = 56 24 wwfe few stfefeud efe fent cfe enfetral fecofe uk: b) Nth term Length of shortest side Length of middle side wwdd ddw stddddud edd ddnt cdd enddtral ddcodd uk. Length of longest side Perimeter Area +2 +1 1 wwbf bfw stbfbfud ebf
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