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Beyond Pythagoras The numbers 3, 4 and 5 satisfy the condition 3²+4²=5², Because 3²= 3x3 =9, 4²= 4x4 =16, 5²= 5x5 =25 And so... 3²+4²=9+16=25=5² I now have to find out if the following sets of numbers satisfy a similar condition of (smallest number) ²+ (middle number) ²= (largest number) ². The numbers 3, 4 and 5 satisfy the condition 3²+4²=5², because 3*3 +4*4 = 5*5 9+16=25 I now have to find out if the following sets of numbers satisfy a similar condition of (smallest number) 2+ (middle number) 2= (largest number) 2. a) 5, 12, 13 5²+12² = 25+144 = 169 = 13². b) 7, 24, 25 7²+24² = 49+576 = 625 +25² Perimeter and area of the right-angled triangles 2) a) Perimeter and area of (5,12,13) triangle: Perimeter = 5+12+13 = 30 Area = 5 x 12 ÷ 2 = 30 Perimeter and area of (7,24,25) triangle: Perimeter = 7+24+25 = 56 Area = 7 x 24 ÷ 2 = 84 b) N A B C P A 1 3 4 5 12 6 2 5 12 13 30 30 3 7 24 25 56 84 I looked at the...

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