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Beyond Pythagoras - Year 10 Maths Coursework
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- Words:
- 3461
- Submitted:
- Thu Jul 11 2002
... Beyond Pythagoras - Year 10 Maths Coursework By Nadia House 10G The numbers 3, 4 and 5 satisfy the condition 3²+4²=5², Because 3²= 3x3 =9 4²= 4x4 =16 5²= 5x5 =25 And so... 3²+4² (=9+16) = 25 (=5²) I now have to find out if the following sets of numbers satisfy a similar condition of: Smallest number² + Middle number² = Largest number² (S² + M = L²) a) 5, 12, 13 5² + 12² = 13² ~ (25 + 144 = 169) b) 7, 24, 25 7²+24² = 25² ~ (49 + 576 = 625) Here is a table containing the results: Short Side Middle Side Long Side 3 4 5 5 12 1 7 24 25 I looked at this table and noticed that there was only a difference of 1 between the length of the middle side and the length of the longest side. I already know that the Smallest number² + Middle number² = Largest number². So I know that there will be a connection between the numbers written above. The only
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