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Mathematics Coursework : The Phone Box Problem
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Mathematics Coursework : The Phone Box Problem Introduction: A woman only has 10 and 20 pence coins to use in a phone box. I have to investigate the number of different ways she could use 10 and 20 pence coins in a phone box. I am also investigating a man who only has 10 and 50 pence coins. I will start off with the woman. 10 pence call 10=10p =1 way 20 pence call 20=10p+10p 20=20p =2 ways 30 pence call 30=10p+10p+10p 30=20p+10p =3 ways 30=10p+20p 40 pence call 40=10p+10p+10p+10p 40=20p+10p+10p 40=10p+20p+10p =5 ways 40=10p+10p+20p 40=20p+20p 50 pence call 50=10p+10p+10p+10p+10p 50=20p+10p+10p+10p 50=10p+20p+10p+10p 50=10p+10p+20p+10p =8ways 50=10p+10p+10p+20p 50=20p+20p+10p 50=20p+10p+20p 50=10p+20p+20p Pascalīs triangle theory This should help me to work out long and write out long equations like the ones I am doing E.g. 50 5 10p =1 1 20p and 3 10p=4 =8 ways 2 20p and 1 10p=3 To get this I used the calculator button which has a big c you put the total number of units at the top then you put the...
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