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Investigating the Gradients of the Graph of the Form ‘y=x2’
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| Submitted: Thu Jul 11 2002
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Investigating the Gradients of the Graph of the Form 'y=x2' Aim To find a formula for the gradient of the graph 'y=x2'. To do this I will draw the graph and measure the gradient at certain whole numbers of 'x'. I will take measurements at: x=1, -1, 2, -3 and 5. Graph Table y=x2 x -5 -4 -3 -2 -1 0 1 2 3 4 5 y 25 16 9 4 1 0 1 4 9 16 25 Calculations To find the gradient on a certain point of the 'y=x2' graph you draw a tangent from a point. Then you form a right-angled triangle on the tangent and find the gradient as for the 'y=ax' graph. (As shown on graph) e.g. 9 9-4= 5 4 2 3-2= 1 3 gradient=y/x =5/1 GRADIENT=5 Results x y Gradient -3 -1 1 2 5 9 1 1 4 25 From these results I believe it is possible to deduce that the...
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