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Investigating the Gradient of a Graph of theForm ‘y=x3’
Member rating: No Rating | Words: | Submitted: Thu Jul 11 2002
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Investigating the Gradient of a Graph of the Form 'y=x3' Aim: To find a relationship between the gradient of 'y= x3' and its formula. Thus working out the gradient function. In this case I will measure the gradient at, -4, -2, 3, and 5. Graph Table y= x3 x -5 -4 -3 -2 -1 0 1 2 3 4 5 y 125 64 27 8 -1 0 1 8 27 64 125 Calculations To find the gradient on a certain point of the 'y=x3' graph you draw a tangent from a point. Then you form a right-angled triangle on the tangent and find the gradient as for the 'y=ax' graph. (As shown on graph) e.g. 27 27-8= 19 8 2 3-2= 1 3 gradient=y/x =3/1 GRADIENT=3 Results x y Gradient -4 -2 3 5 64 8 27 125 Conclusion From these results I can conclude that the gradient function for the graph 'y= x3' is 3x2. To test this result I can predict that the gradient at x=0.5, will be...
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