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Emma's Dilemma.
Member rating: No Rating | Words: | Submitted: Thu Oct 23 2003
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Maths Coursework 2002 Emma's Dilemma Rory O'Connell The Aim of this investigation is to see how many combinations of letters there are in names and other letter combinations. For example the name Emma has the following combinations: EMMA EAMM EMAM AMEM AMME AEMM MEAM MAEM MEMA MAME MMEA MMAE In the word EMMA there are 12 possible combinations These are the possible combinations for the word LUCY: LUCY UYLC LUYC UYCL LCUY UCYL LCYU UCLY LYUC LYCU CLYU CLYU CULY CUYL CYUL CYLU YLUC YLCU YCUL YCLU YULC YUCL ULCY ULYC In the word LUCY there are 24 possible combinations. Twice the amount of arrangements in the word EMMA, despite having the same amount of letters. I then looked at the number of combinations of letters there were in names of varying length: JO SAM FRED DARYL GERALD I did this by writing out all the possible combinations for each name, For example: SAM SMA AMS ASM MAS MSA And JO OJ Results Table Name Number Of Combinations JO 2 SAM 6 FRED 24 LUCY 24 EMMA 12 DARYL 120 GERALD 720 I have found an equation, which will tell you the number of letter combinations in each word (except EMMA), it is based on the following idea: In the word FRED for example, there are four letters. When rearranging the letters, there are...
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