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Emma's Dilemma
Member rating: No Rating | Words: | Submitted: Thu Jul 11 2002
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GCSE COURSEWORK Matthew Kilgour 25/8/01 Arrangements for Emma: 4 letters, 2 the same. 1.emma 2.emam 3.eamm 4.mmae 5.mmea 6.meam 7.mema 8.mame 9.maem 10.amme 11.amem 12.aemm In a word/name with 4 letters and none the same, then there are 24 possible arrangements. There are 12 possibilities; note that there are 4 total letters and 3 different. Emma has four letters, three of which are different. This means that it only has 12 possible combinations. I had noticed that 4 (number of total letters) multiplied by 3 (the number of different letters) equals 12. What if all the letters were different like in Lucy? Arrangements for Lucy: 4 letters, all different, none the same. As I stated before, in a word with 4 letters and none the same, there are 24 possible combinations, double the number of combinations for Emma, which has 4 letters and 3 the same. 1.lucy 2.luyc 3.lcyu 4.lycu 5.lcyu 6.lyuc 7.ulcy 8.ucly. 9.uylc 10. ulyc...
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