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Emma's Dilemma I am going to investigate the number of different arrangements of various groups of letters. I will start with the number of arrangements for words with all the letters being different. For this I will use the name LUCY. For example, LCUY is one arrangement YUCL is another. Here are all the combinations of letters in the name LUCY: LUCY UCYL CYUL YCUL LUYC UCYL CYUL YCUL LCUY ULCY CULY YUCL LCYU ULYC CUYL YUCL LYUC UYCL CLYU YLCU LYCU UYLC CLUY YLUC There are 24 different combinations of letters with 4 letters being all different. I have noticed that there are six combinations with each letter at the start of the word. So, you do 6x4 to find out how many combinations there are. This means that for all words with different letters, there's going to be 24 combinations. I then noticed that the total number of combinations is the number of letters multiplied by the previous number...

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