Coursework.Info - Inspiration in an Instant

On the left is an image preview of every page of this document, and below are the first 150 words with formatting removed:

Emma's dilemma Every name has many ways of arranging the letters e.g. BOB, OBB, BBO. I am trying to find a pattern and formula for finding out how many combinations there for a name. I tried different names with a different number of letters in them, I also tried the names with repeated letters in them. There are several methods of finding out the combinations of a name, I have used 3 different methods. Method 1 Listing Two lettered names ED DE 2 ways Three lettered names As you can see below a three lettered name with 1 repetion in it has half the number of combinations. TED TDE ETD EDT DTE DET 6 ways BOB BBO OBB 3 ways Four lettered names I have noticed that with four lettered names that with 1 letter repeated there are half the number of combinations and halved again if there are two pairs of letters LUCY EMMA LCUY EAMM LYCU EMAM LCYU AEMM LYUC AMEM LUYC AMME ULCY MMAE ULYC MMEA ULYC MEMA UYLC MAME UCLY MEAM UCYL MAEM CLUY 12 ways CLYU CYUL LULU CYLU LUUL CUYL...

To see the full version of this document, and 145,348 others