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EMMA'S DILEMMA Aim To investigate the patterns caused by the permutations of letters in words of different lengths and to investigate the possibility of predicting the number of permutations. To discover a formula that can be applied to all words. Question 1. 12 different permutations can be made by the name EMMA: 1. EMMA 2. EMAM 3. EAMM 4. MMEA 5. MMAE 6. MEMA 7. MEAM 8. MAEM 9. MAME 10. AMEM 11. AMME 12. AEMM Question 2. 24 different permutations can be made by the name LUCY: 1. LUCY 2. LUYC 3. LYUC 4. LYCU 5. LCYU 6. LCUY 7. CULY 8. CUYL 9. CYUL 10. CYLU 11. CLUY 12. CLYU 13. UYCL 14. UYLC 15. ULYC 16. ULCY 17. UCYL 18. UCLY 19. YLCU 20. YLUC 21. YULC 22. YUCL 23. YCUL 24. YCLU This is double the amount of permutations made by EMMA Question 3 CLIVE 1. CLIVE 2. CLIEV 3. CLVIE 4. CLVEI 5. CLEVI 6. CLEIV 7. CEIVL 8. CEILV 9. CEVLI 10. CEVIL 11. CELIV 12. CELVI 13. CILVE 14. CILEV 15. CIVLE 16. CIVEL 17. CIEVL 18. CIELV 19. CVLEI 20. CVEIL 21. CVIEL 22. CVILE 23. CVLEI 24. CVLIE 25. LCEVI 26. LCEIV 27. LCVEI 28. LCVIE 29. LCIVE 30. LCIEV 31. LIEVC 32. LIEVC 33. LIVCE 34. LIVEC 35. LICVE 36. LICEV 37. LICIV 38. LECVI 39. LEICV 40. LEIVC 41. LEVCI 42. LEVIC 43. LVEIC 44....

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