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Emma’s Dilemma.
Member rating: No Rating | Words: | Submitted: Mon Dec 15 2003
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Emma's Dilemma Introduction In this mathematics coursework, I am investigate and find out the different combinations in a word after I have done this will be trying to find out a formula that will allow me to find out the different combinations quicker without showing all the different outcomes, and what I am also going to do is find a formula which will enable combinations easier for a word with repeated letters. Different arrangements in the word LUCY (four letter word) LUCY ULCY CLUY YLUC LUYC ULYC CLYU YLCU LCUY UCLY CULY YULC LCYU UCYL CUYL YUCL LYUC UYLC CYLU YCLU LYCU UYCL CYUL YCUL Number of combinations= 24 What I did to find out all the outcomes in the word LUCY was keeping the first two letters in the same place then just swapping the last two letters around until I was enable to find any more Letter(s) Number of letters Total combinations L 1 1 LU 2 2 LUC 3 6 LUCY 4 24 1?2?3?4=24 combinations for the word LUCY Different arrangements in the word EMMA (four letter word with same letters) EMMA MEMA AMME EAMM MAME AEMM EMAM MMEA AMEM MMAE MEAM MAEM Number of combinations= 12 If you do not divide the amount...
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