Emmas Dilemma.
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EMMA's Dilemma We are investigating the number of different arrangements of letters. Firstly we arrange EMMA's Name. 1)EAMM 7)MAEM 2)EMAM 8)MAME 3)MEMA 9)AMME 4)MEAM 10)AEMM 5)MMEA 11)AMEM 6)MMAE 12)EMMA Secondly we arrange lucy's name. 1)Lucy 12)Cyul 22)Yulc 2)Luyc 13)Culy 23)Ycul 4)Lycu 14)Culy 24)Yluc 5)Lcuy 15)Cylu 25)Ucyl 6)Lcyu 16)Clyu 7)Ulcy 17)Cuyl 8)Ucly 18)Yluc 9)Uycl 19)Yucl 10)Ulyc 20)Yclu 11)Uylc 21)Ylcu From these 2 investigation I worked out a method: Step1: 1234---Do the last two number first then you get 1243. 1243---Do the last three numbers and try the possibility. 1423. 1432. 1342. 1324, because the number 2 has been the first number of last three numbers, so we don't do it again. Step2: we have list all arrangements of 1 go front, so we do 2 go front. 2134 and we do same thing to it, it will like this: 2134---2143, 2143---2431,2413,2314,2341 Step3: We have finished 2 go first, then let's do 3 go ahead. 3124---3142, 3142---3241,3214,3412,3421 Step4: We have finished 3 go ahead, then try 4 4123---4132, 4132---4231,4213,4312,4321 We have list all arrangement of...


