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Emma's Dilemma In my investigation I am going to investigate the number of different arrangements of letters in a word. e.g. Tim Is one arrangement. Mit Is another. First I am going to investigate how many different arrangements in the name LUCY, which has no letters the same. LUCY UCYL CYLU YULC LUYC UYLC CYUL YUCL LCYU UCLY CLUY YLUC LCUY UYCL CLYU YLCU LYCL ULCY CUYL YCLU LYLC ULYC CULY YCUL There are 4 different letters and there are 24 different arrangements. As you can see, the method i have used to make sure that I have found the correct amount of arrangements is that there are 4 letters and each letter should have 6 different arrangements. Two with the same second letter, then another two with a different second letter, and then the last two also have the same second letter. SAM SMA MSA MAS ASM AMS There are 3 different letters in this name and 6 different arrangements. Again, as you can see there a pattern to how I have worked out the correct amount of arrangements, there are 2 different letters after the...

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