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Emma’s Dilemma
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| Submitted: Thu Jul 11 2002
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Luke Plant 10S8 Emma's Dilemma 11/06/2002 In my investigation I am going to investigate the number of different arrangements of letters in a word any try to find any formulae and patterns. An example of this would be: - Tim And another arrangement is: - Mit First I am going to investigate how many different arrangements in words, which have no letters the same. DATA 1a) There are 2 different letters in this name and 2 different arrangements. JO OJ 1b) There are 3 different letters in this name and 6 different arrangements SAM SMA MSA MAS ASM AMS 1c) There are 4 different letters and there are 24 different arrangements LUCY LUYC LYCU LYUC LCYU LCUY ULCY ULYC UCYL UCLY UYLC UYCL CULY CUYL CYUL CYLU CLUY CLYU YLUC YLCU YUCL YULC YCUL YCLU . Table of Results Number of Letters Number of Differentnts 2 2 3 6 4 24 From the table of results I have found out that a 2-letter word has 2 arrangements, and a 3-letter word has 6. The pattern I see emerging is that of N! (N being No. of letters) This is true for all of the words in...
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