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This experiment is to investigate if CaCl2 and Na2CO3 in Distilled Water, Hydrochloric Acid, Sodium Hydroxide, Butanol and Ethanol at room temperature.
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Sagar Manilal 15-Nov-2003 Chemistry Lab: Solubility of Solids Aim This experiment is to investigate if CaCl2 and Na2CO3 in Distilled Water, Hydrochloric Acid, Sodium Hydroxide, Butanol and Ethanol at room temperature. Hypothesis This investigation is to see which one of the two solids dissolves in which of the liquids. These solids are CaCl2 and Na2CO3. I find that Na2CO3 may be more soluble in the liquids as the Na is an element that can lose only 1 electron unlike Ca that needs to lose 2. However I find that the difference will be minute since the ionization energies are both in the s-shell. Na has an s-shell missing so it is more likely to lose 1 electron unlike Ca that needs to lose 2. This is difficult for the Calcium as the number of protons remains the same and is having a greater pull on the electrons after losing 1 electron. Another factor that should...
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