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The determination of a rate equation  

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The determination of a rate equation Introduction After watching the demonstration shown by the teacher, I noticed a cloudy solution forming within 10 seconds after mixing the 50cm³ of (0.4 moldm-³) Na2S2O3 was mixed with 5.0 cm³ HCL (2.0 moldm-³) diluted with 20cm³ H2O. From this I can simply conclude that the reaction takes place quickly and further increasing concentration/ volumes would produce a faster reaction. This would make it difficult to measure the exact point when a cloudy solution is formed. If the time taken to produce the cloudy solution is faster than 10seconds this increases the chance of error and inaccuracy as the time taken for detection from the eye and time to respond by stopping the stop clock can lead to an error of judgement within +5 seconds, this would be too great if the reaction was carried out at a greater concentration/ volumes. I know SO2 is produced from...

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