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Reacting SodiumThiosulphate with dilute Hydrochloric acid.
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| Submitted: Fri Oct 24 2003
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By Chris Augustine Introduction Last month the class and I did an experiment in which we reacted Sodium Thiosulphate with dilute Hydrochloric acid. The chemical equation was: (Na2S2O3(aq) + 2HCl(aq) 2NaCl(aq) + H2O(l)+S(s)+SO2(g) We did this in a beaker with a piece of paper underneath with a large X on it. We did this over and over again with more concentrated Thiosulphate each time to see how the CONCENTRATION of the reaction affected its RATE OF REACTION. The reaction forms a precipitate of Sulphur, which becomes cloudy and eventually covers the X completely. We measured the rate by timeing hoe long it took for the X to disappear. Background Knowledge The particles of the reactants need to meet three requirements to form a reaction. ONE: The particles have to collide with enough ENERGY, TWO: The particles need to collide at the right ANGLE and, THREE: The particles need to collide at the right SPEED. Without these three...
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