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Determination of the Formula of a Compound
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Determination of the Formula of a Compound Results Mass of crucible and lid 23.0899g Mass of crucible, lid and Mg 23.1535g Mass of crucible, lid and product 23.1894g Mass of Mg used = 0.0636g (Mass of crucible, lid and Mg 23.1535 - Mass of crucible and lid 23.0899) Mass of Product found = 0.0995g of Mg Oxide (Mass of crucible, lid and product 23.1894g - Mass of crucible and lid 23.0899g) Mass of O used in reaction =0.0359g (Mass of Mg used 0.0636g - Mass of Product found 0.0995g) Ratio of Mg to O by mass... Mg mass used 0.0636 Ratio Mean Mass of O used 0.0359 Atomic Mass 24 Atomic Mass 16 =0.00265 =0.00224375 Divide the smallest by the largest (0.00265/0.00224375) gives the ratio number of mole. Mg: 1.18105 O: 0.08466 Conclusion Oxygen is a very good oxidizing agent. In the process, oxygen is reduced to O2- ions. Burning magnesium ribbon produces MgO in the presence of oxygen: 2Mg(s) + O2(g) 2MgO(s) Thus, my results should have...
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