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'The Molecular Formula of Succinic Acid' The aim of this experiment is to determine the molecular formula of a sample of anhydrous succinic acid. Succinic acid is a diprotic, which means it donates two protons per molecule. Succinic acid can be completely neutralised by sodium hydroxide. The indicator most suitable for this experiment is phenolphthalein, it is colourless in acids and pink in alkalises. The half way stage is about pH 9.3, this is when it will either change from colourless to a very pale pink or from pink to colourless. To determine the relative formula mass of succinic acid I am going to do a titration against sodium hydroxide. The equation for the reaction is given below. To make the equation easier to read, HOOC(CH2)nCOOH will be condensed to H2A because of the two hydrogen atoms at either end. H2A+2NaOH --> Na2A+2H2O (CV) H2A = 1 (CV) NaOH...

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