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Working out the concentration ofThiosulphate solution and amount of HCl to be used
Member rating: No Rating | Words: | Submitted: Mon Mar 14 2005
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Working out the concentration of Thiosulphate solution and amount of HCl to be used I will firstly work out the concentration of Thiosulphate solution: Volume of Thiosulphate = 50 cm3 40g/ litre = 40 grams in 1000 cm3 Relative Molecular Mass (RMM) of Thiosulphate = 158 g Concentration: 1 Mole of Thiosulphate contains 158 grams in 1000 cm3 0.25 Moles of Thiosulphate contains 40 grams in 1000 cm3 Therefore the concentration of Thiosulphate = 40/ 158 = 0.25 moles of Thiosulphate in 1000 cm3 Number of moles in 50 cm3 of thiosulphate: 0.25 moles in 1000 cm3 in 50 cm3, moles = 50/ 1000 = 0.05 moles Therefore number of moles of thiosulphate in 50 cm3 = 0.0125 I will now calculate the number of moles of Thiosulphate needed to react with hydrochloric acid: Na2S2O3 + 2HCl 2NaCl (aq) + H2O + SO3 + S(s) 50 cm3 / 0.0125 Number of moles of HCl = 2 x 0.0125 = 0.025 I will now work...
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