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The purity of aminosulphonic acid
Member rating: No Rating | Words: | Submitted: Mon Jan 29 2007
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The purity of aminosulphonic acid Titration number 1 2 3 4 Final burette reading/cm3 23.30 22.50 45.10 23.50 Initial burette reading/cm3 0.00 0.10 22.40 1.00 Amount of acid used for each titration: 1- 23.00-0.00=23.00 cm3 2- 22.50-0.10=22.40 cm3 3- 45.10-22.40=22.70 cm3 4- 23.50-1.00=22.50 cm3 The amount of acid used for the first titration is a little higher than it should be so to make the calculation much more accuracy I will ignore the first one and I will work out the average of the other three values: 22.40+22.70+22.50=67.6 cm3 67.6/3=22.53 cm3 (2 decimals place) 22.53 cm3 is average amount of acid (H2NSO3H) reacted with 25.00 cm3 of alkali (NaOH) with concentration of 0.200 moldm-3. Now I am going to work out the number of moles of NaOH in 25.00 cm3 of that with concentration of 0.200 moldm-3: CV=M C=0.200 moldm-3 M=0.200*25.00/1000=0.005 number of moles of NaOH V=25.00 cm3 reacted with acid. M=number of moles As the ratio of the acid to the alkali in the reaction is 1-1 so number of moles of the acid...
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