The dehydration of Cyclohexanol to form Cyclohexene.
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| Submitted: Thu Sep 11 2003
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The dehydration of Cyclohexanol to form Cyclohexene. In order to dehydrate Cyclohexanol it is required that a dehydration agent, in this case phosphoric acid, be added and for the mixture to be distilled with the Cyclohexene being taken off between 343K and 363K. This reaction gives the formula: In order to keep the experiment at a manageable size 0.1 mole of Cyclohexanol was used along with 4cm3 of concentrated Phosphoric acid. 0.1 mole of Cyclohexanol x 100.2 = 10.2 100.2 0.962 = 10.4 cm3 However because the measuring cylinder only measured to the nearest 1cm3 ,10cm3 had to be used instead. This volume was placed into a 50cm3 pear shaped and the 4cm3 of phosphoric acid was added slowly while shaking the flask. The flask was then attached to the rest of the apparatus as shown below; Because the boiling point of Cyclohexene is 356K and for water it is373K it was...

