Logged out
Access All our Essays in an Instant
Swap your work for FREE access, or pay £4.99 for instant access
The Relative Strength of an Unknown Acid
Member rating: No Rating | Words: | Submitted: Mon Jun 06 2005
Page Preview
On the left is an image preview of every page of this document, and below are the first 150 words with formatting removed:
The Relative Strength of an Unknown Acid Practical Details Mass of acid: 12.38g Initial temperature of acid: 21.7 °C Table of Results Temperature change during reaction between acid and 1.00M Sodium Hydroxide solution: Time (minutes) Temperature (°C ) 0 23.1 1 23.1 2 23.1 3 23.1 4 acid added - 5 26.9 6 26.6 7 26.3 8 26.0 9 25.8 10 25.6 Analysis * The graph suggests that the temperature rise that occurred at the fourth minute was: 26.9 - 23.1 = 3.8 °C * Given the Mr of the acid is 50, the moles of acid in my solution, n = m / Mr = 12.38 / 50 = 0.248 moles. * So the concentration of my solution, c = n/v which is 0.248 / 0.25 = 0.992 mols/dm³ * Therefore the heat given out in Joules, q = mc?T = 100 x 4.18 x 3.8 = 1588J Using this information I can calculate the molar enthalpy change of neutralisation for the acid: Firstly, how many moles are there in 50 cm³? - 0.992 x 0.05 = 0.0496 moles Therefore the enthalpy change...
Get instant access
- Instant, unlimited access to our documents in full
- Swap your work for free access, or pay £4.99
- To see the full version of this document and 150,117 others
