Neutralisation Points
Member rating: No Rating | Words: 5136 | Submitted: Mon Jan 28 2008
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OBTAINING EVIDENCE I first did a quick run through, every 1cm³ of 1moldm-3 HCL added (to 1moldm-3 NaOH) and left for 30s. I gained the following results: VOLUME HCL added (cm³) TEMPERATURE (°C) 0 22.0 1 23.0 2 23.5 3 23.5 4 24.0 5 24.5 6 25.0 7 25.5 8 25.5 9 26.0 10 26.0 11 26.5 12 27.0 13 27.0 14 27.5 15 27.5 16 28.0 17 28.0 18 28.0 19 28.0 20 28.5 21 29.0 22 29.0 23 29.0 24 28.5 25 28.5 26 28.5 27 28.0 28 28.0 29 28.0 30 28.0 31 28.0 32 28.0 33 27.5 34 27.5 35 27.5 As I had previously stated I would repeat my results to make sure that they are accurate. Here is my second table of results. VOLUME HCL added (cm³) TEMPERATURE (°C) 0 22.0 1 23.0 2 23.0 3 23.5 4 24.0 5 24.5 6 25.0 7 25.5 8 25.5 9 26.0 10 26.0 11 26.5 12 27.0 13 27.5 14 27.5 15 28.0 16 28.0 17 28.0 18 28.0 19 28.5 20 29.0 21 29.0 22 29.0 23 29.0 24 28.5 25 28.0 26 28.0 27 28.0 28 28.0 29 28.0 30 28.0 31 28.0 32 28.0 33 27.5 34 27.5 35 27.5 These results show me that at 28.5°C the temperature changes therefore this shows me that this occurs when 24 cm³ of acid (HCl) is added. I have decided to repeat my test but this adding 0.5 cm³ of HCl, I feel it unnecessary to measure the temperature for each volume of acid added I will to go straight to 19 cm³ as this is a few cm³ before the temperature change. This new table shows me that it is at 24.5 cm³ of HCl added that the temperature changes. VOLUME HCL added (cm³) TEMPERATURE (°C) 19.0 27.5 19.5 27.5 20.0 27.5 20.5 27.5 21.0 28.0 21.5 28.0 22.0 28.0 22.5 28.0 23.0 28.0 23.5 28.0 24.0 28.0 24.5 28.0 25.0 27.5 With the indicator test; it...

