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Determination of the solubility of calcium hydroxide I have to plan an experiment to find the solubility of calcium hydroxide, Ca(OH)2, in water. I have to make up a solution of calcium hydroxide and carry out a titration using hydrochloric acid solution of the chosen concentration. The equipment need is as below: * Solid calcium hydroxide * Methyl orange indicator * Volumetric flask (250cm3) * Clamp and boss * Clamp stand * Burette (50cm3) * Conical flask * Pipette (25cm3) * Pipette filler * Distilled water * White spotting tile * Hydrochloric acid of chosen concentration * Beaker x2 * Rubber bung * Funnel x2 * Electronic scale 'The maximum mass of calcium hydroxide needed to produce 1dm3 of saturated solution at room temperature is 1.5g.' I only want 250cm3 as I am using a 250cm3 volumetric flask. Therefore: 1dm3 / 4 = 250cm3 1.5g / 4 = 0.375g The number of moles in volumetric flask: 0.375 / 74 = 0.005 moles I need an excess of 0.5g to make sure...

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