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Endothermic Reactions.
Member rating: No Rating | Words: | Submitted: Tue May 18 2004
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Endothermic Reactions I am going to investigate the temperature drop induced by the reaction: NH4Cl + 100 H20 = NH4Cl (aq 100 H20) Calculating the amount of solid required to react with a certain amount of water NH4Cl + 100 H20 = NH4Cl (aq 100 H20) 1 mole NH4Cl = 14 + 4 + 35.5 = 53.5g 1 mole H20 = 2 + 16 = 18g/cm3 (assuming that 1g is the same as 1cm3) It can therefore be assumed that one mole of water occupies 18cm3 of space. Ratio: NH4Cl : H20 1 : 100 53.5 : 18*100 53.5/18 : 1800/18 2.97 : 100 Plan I will take 100cm3 of water and 2.97g of NH4Cl and combine them in a polystyrene beaker whilst measuring the change in the temperature with an accurate thermometer (accurate to 0.1cm3). I will surround my beaker with cotton wool wadding and a sheet of aluminium foil shiny side in to reduce heat loss. I will also make a cardboard lid surrounded...
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