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Determining the Relative Atomic Mass of Lithium
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Chemistry Course work Determining the Relative Atomic Mass of Lithium Method 1:By measuring the volume of hydrogen produced 2Li(s) + 2H2O(aq) -- 2LiOH(aq)+H2(g) Mass of Lithium used = 0.10g Amount of Hydrogen gas evolved = 168 cm³ Calculations 1) Calculate the number of moles of hydrogen Number of moles of hydrogen = Volume of hydrogen/molar volume = 168cm ³/24000cm³ = 0.007________ 2) Deduce number of moles of Lithium According to the reacting equation: 2Li(s) + 2H2O(aq) -- 2LiOH(aq)+H2(g) The ratio of moles of lithium used to hydrogen produced is 2:1 So since in the experiment we have produced 0.007 moles of H2 (g) The number of moles of Li = 2 x number of moles of hydrogen =2 x 0.007 =0.014 3) Therefore calculate the Ar (Li) NB* Ar (Li) = mass of one mole of Lithium So if 0.014 moles are to 0.10g...
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