Coursework.Info - Inspiration in an Instant

On the left is an image preview of every page of this document, and below are the first 150 words with formatting removed:

Introduction/Plan: The aim of this investigation is to determine the concentration or molarity of Ethanoic acid (CH3COOH) in two types of commercial vinegar. To set about this, values of percent by mass have been noted from the internet and the modal value for this was 5%. The concentration can be calculated from percentage by mass by doing this: 5% ethanoic acid in vinegar can be interpreted by saying that it is the same as 5 grams of acid per every 100 grams of solution so: The number of moles of ethanoic acid must first be calculated: No. Mole = Mass/Mass of one Mole. The molecular mass of ethanoic acid must then be calculated which is 60. No. mole = 5/60 = 0.083 mole (to 2 d.p.) Therefore the number of mole in 1000 grams of solution can be found which will be useful as this is approximately equal to 1 dm3 and means that the final...

Get instant access

• Instant, unlimited access to our documents in full
• Swap your work for free access, or pay £4.99
• To see the full version of this document and 146,871 others

OR

Receive email updates for this category

• Simply tell us your email address and receive a weekly Study Help Email for FREE
• Receive 3 FREE essay views with each email
• Get all the latest essays from Coursework.Info & discussion from TheStudentRoom.co.uk