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Determination of the relative atomic mass of lithium To calculate the relative atomic mass of lithium I am going to use two methods. Method 1: I am going to measure the volume of hydrogen produced when a known mass of lithium reacts with H2O Method 2: I will now titrate the solution of lithium hydroxide produced. Method 1 results Mass of lithium (g) Volume of hydrogen produced (cm3) 1: 0.09 173 2: 0.09 176 Treatment of results Assuming that one mole of gas occupies 24000cm3 at room temperature and pressure. 2Li (s) + 2H2O (l) › 2LiOH (aq) H2 (g) I am going to calculate the number of moles of hydrogen, H2 that I had collected: No. of moles = V÷ 24000 V = amount of hydrogen collected 1: 173÷24000 = 0.0072083mols (Li) 2: 176÷24000 = 0.0073333mols (Li) I will now deduce the number of moles of lithium that reacted: 2 x molls of H2 1: 0.0072083 x 2 = 0.0144166mols 2: 0.0073333 x 2 = 0.0146666mols Now...

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