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Determination of the relative atomic mass of magnesium.
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Determination of the relative atomic mass of magnesium Method 1 - RSULTS: Assume that 1 mole of gas occupies 24 000 cm3 at room temperature and pressure. Mg(s) + 2HCl (aq) --> MgCl2(aq) + H2 (g) Calculate the number of moles of hydrogen you collected. Mg(s) + 2HCl (aq) --> MgCl2(aq) + H2 (g) Ratio Magnesium: Hydrogen is 1:1 Number of moles = Amount of hydrogen produced / 24000 Hydrogen = 142 / 24000 = 0.00592 moles Deduce the number of moles of magnesium Number of moles = 1 x 0.00592 Magnesium =0.00592 moles Calculate the relative atomic mass of magnesium RAM = Mass / Number of moles = 0.12 / 0.00592 = 20.27 Method 2 - RESULTS Mass (g) Weight of clean evaporating basin 31.70 Weight of evaporating basin + conical flask contents 41.64 Weight of evaporating basin + solid magnesium chloride 32.22 Calculate the mass of magnesium chloride formed Weight of evaporating basin and - Weight of clean evaporating basin solid magnesium chloride = 32.22 - 31.70 = 0.52 g Calculate...
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