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Determination of the relative atomic mass of lithium The aim of this experiment is to determine the relative atomic mass of lithium. I will be doing this in two ways: the first method will be to collect the gas evolved when lithium is reacts with distilled water and calculate the relative atomic mass this way. The second method will be to calculate the relative atomic mass through titration. ANALYSIS - Method 1 The volume of hydrogen collected from the reaction of 0.05 grams of lithium with 100.0cm3 was 90.3cm3. The chemical equation for this is: 2Li(s) + 2H2O(l) 2LiOH(aq) + H2(g) The mole ratio of lithium to hydrogen is: 2:1 First I must calculate the number of moles of hydrogen, I can do this using the following equation: Number of moles of gas = volume 24 000 (one mole of any gas has a volume of 24 dm3 RTP) Therefore, the number of moles of hydrogen = 90.3cm3 24 000cm3 = 3.7625...

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