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Determination of the relative atomic mass of Lithium Implementing For all my results I have decided to use three significant figures. This is because the apparatus I was told to use for the experiment gave me results to three significant figures. There was, therefor, no point in calculate to any further accuracy as this would just define a figure that has already been calculated to a specific depth of accuracy. Results Method 1 Mass of Lithium used 1.09 g Volume of gas produced 175 cm3 Method 2 1 2 3 Final Burette Reading 42.1 42.3 42.3 Initial Reading 0 0 0 Volume added (cm3) 42.1 42.3 42.3 Average 42.2 cm3 Analysing Method 1 Calculate the number of moles of hydrogen. 1) 175 = 0.00729 Number of moles = Amount of gas produced 2400 2400 This was calculated to find out the number of moles in the Hydrogen gas that had produced. Deduce from this the number of moles of Lithium. 2) The number of moles of Lithium = 0.00729 x 2= 0.0146 If you look at the chemical equation-...

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