Logged out
Access All our Essays in an Instant
Swap your work for FREE access, or pay £4.99 for instant access
Determination of the relative atomic mass of lithium
Member rating:
(1 vote)
| Words:
| Submitted: Mon Sep 08 2003
Page Preview
On the left is an image preview of every page of this document, and below are the first 150 words with formatting removed:
AS Assessed Practical Determination of the relative atomic mass of lithium Results - method 1 Mass of lithium used - 0.10g Volume of hydrogen evolved - 188.00cm Results - method 2 Rough Accurate 1 2 Initial volume reading (cm³) 0.00 0.00 0.00 Final volume reading (cm³) 34.69 34.98 38.94 Volume used (cm³) 34.69 34.98 38.94 Average volume of Hydrochloric Acid used = 34.98 + 34.94 / 2 = 34.96 cm Calculations - method 1 2Li + 2H2O 2LiOH +H2 2 moles 1 mole 1 mole of gas occupies 24000cm³ at RTP Volume of H2 gas evolved = 188cm³ 188 / 24000 = 0.0078 moles 0.0078 2 = 0.016 moles (2sf) Ar = 0.10 / 0.016 = 6.383 (3dp) Calculations - method 2 LiOH + HCl LiCl + H2O 1 mole 1 mole 0.10 34.96 / 1000 = 0.003496 moles = 0.0035 (2sf) moles in 25cm³of LiOH 0.003496 x 4 = 0.013984 moles = 0.014 (2sf) moles in 100cm³ of LiOH Ar = 0.10 / 0.013984 =7.15 (2dp) Evaluation Overall both of the procedures for finding the relative atomic mass of lithium were relatively successful although none of...
To see the full version of this document, and 145,841 others
