Your Status: Logged out Log in

Determination of the formula of Hydrated Iron(II) Sulphate Crystals

Member rating: 8 out of 10 stars (1 vote) | Words: 1223 | Submitted: Sun Aug 26 2007

Page Preview
Preview
Previous 1 of 3 Next

On the left is an image preview of every page of this document, and below are the first 150 words with formatting removed:

Determination of the formula of Hydrated Iron(II) Sulphate Crystals Hydrated FeSO4 can come in many hydrated forms. Using two methods for better accuracy and to make a comparison, I will deduce the number of water molecules per mole of a hydrated iron(II) sulphate sample. Method 1: FeSO4.nH2O(s) › FeSO4(s) + nH2O(l) =dehydrating the FeSO4 by evaporating the water and calculating the mass lost. Hazards in this experiment include the flame from the Bunsen and the possibility of the crucible shattering. By using a gentle heat for two minute intervals and the lid slightly ajar (but not so the contents might spit) the crucible shouldn't spit and the water can escape. The reactant (FeSO4) is not dangerous, unless consumed in large doses. Results: Crucible, lid and FeSO4= 21.76g FeSO4= 1.41g Heating Mass after heating(g) Overall loss(g) 1 21.10 0.66 2 21.10 0.66 3 21.10 0.66 4 21.10 0.66 All four results show one and no further mass change meaning the water has been evaporated leaving just the iron(II) sulphate. Analysis: Out of the...

Get instant access



  • Instant, unlimited access to our documents in full
  • Swap your work for free access, or pay £4.99
  • To see the full version of this document and 146,871 others
Register Now
OR

Receive email updates for this category



  • Simply tell us your email address and receive a weekly Study Help Email for FREE
  • Receive 3 FREE essay views with each email
  • Get all the latest essays from Coursework.Info & discussion from TheStudentRoom.co.uk