Your Status: Logged out Log in

Determination of the formula of Hydrated Iron (II) Sulphate Crystals  

Member rating: No Rating | Words: | Submitted: Wed Nov 01 2006

Page Preview
Preview
Previous 1 of 4 Next

On the left is an image preview of every page of this document, and below are the first 150 words with formatting removed:

Analysis Method 1 Results Trials Mass of FeSO4.XH2O (g) Mass of crucible + FeSO4.XH2O at start (g) Total Mass at start (g) Mass of crucible + FeSO4 at the end (g) Difference in start and end values (g) 1 1.37 11.17 12.54 11.93 0.61 2 1.61 11.06 12.67 12.12 0.55 3 1.50 11.43 12.93 12.43 0.50 For greater accuracy, we have taken three trials and therefore three sets of results. To combine these into one single, accurate answer, we will need to take an average of the 3 values in the 'difference in start and end values' column. This is done below: Average difference in start and end values = g (3 s.f.) We will also need to take an average of the 3 'mass of FeSO4.XH2O' values. This is done below: Average mass of FeSO4.XH2O = (3 s.f.) Now we are able to deduce the formula of the FeSO4.XH2O since we only have two values. First we shall work out the amount of FeSO4 that was originally within the FeSO4.XH2O. This is done below: Mass of H20 within FeSO4.XH2O =...

Get instant access



  • Instant, unlimited access to our documents in full
  • Swap your work for free access, or pay £4.99
  • To see the full version of this document and 146,871 others
Register Now
OR

Receive email updates for this category



  • Simply tell us your email address and receive a weekly Study Help Email for FREE
  • Receive 3 FREE essay views with each email
  • Get all the latest essays from Coursework.Info & discussion from TheStudentRoom.co.uk