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Determination of the Relative Atomic mass of Lithium
Member rating: No Rating | Words: | Submitted: Thu Jan 13 2005
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Determination of the Relative Atomic mass of Lithium Implementing Method 1: Gas Syringe 2Li(s) + 2H2O(l) 2LiOH(aq) + H2(g) From a Mass of 0.0463g of Lithium, I measured that 55.0cm3 of Hydrogen gas was given off when the Lithium reacted quite vigorously with the Distilled water. Method 2: Titration LiOH(aq) + HCl(aq) LiCl(aq) + H20(l) When titrating the Lithium Hydroxide solution against Hydrochloric acid I have obtained the following results: Initial Volume (cm3) Final Volume (cm3) Difference in Volume (cm3) Rough 10.05 20.04 09.99 Titration 1 10.00 20.95 10.95 Titration 2 09.95 20.90 10.95 Titration 3 10.00 20.90 10.90 From these results I have obtained 3 results within 0.5 cm3 of each other, but seeing as I have 10.95 two times, I can leave my result of 10.90 out of my calculation to obtain the average difference, and so 10.95cm3 will be used when I calculate the Relative atomic mass of Lithium. Throughout both experiments I wore safety goggles and a lab coat to ensure my safety around the Hydrochloric acid and the Lithium Hydroxide as...
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