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Determination of the Relative Atomic Mass of Lithium.
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Chemistry Coursework Determination of the Relative Atomic Mass of Lithium. VICTORIA OLIPHANT Method 1 Equation 2Li(s) + 2H2O(l) › 2LiOH(aq) + H2(s) Results ORIGINAL MASS OF LITHIUM 0.10g VOLUME OF H2 182cm3 In order to calculate the number of moles of hydrogen this equation needs to be used in conjunction with the results obtained above: Number of moles = Volume (cm3) 24,000 n = Vcm3 24,000 n = 182cm3 24,000 n = 0.00758 mol (3sf) To deduce the number of moles of lithium I needed to look at the ratio between the lithium and hydrogen, which can be seen in the equation: 2Li(s) + 2H2O(l) › 2LiOH(aq) + H2(s) Ratio = 2:1 From this information and the number of moles of hydrogen, (worked out above) I can work out the number of moles of lithium. This is because double the amount of lithium to hydrogen is going to be needed: 0.00758 x 2 = 0.01516 mol = 0.0152 mol (3sf) Therefore with the...
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