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Concentration of Solutions - Introduction
Member rating: No Rating | Words: | Submitted: Thu Aug 21 2003
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oncentration of Solutions - Introduction Some measure of the amount of solute dissolved in a solvent is needed when dealing with solutions (particularly aqueous solutions). e.fg. mass per unit volume : g cm-3, kg m-3 or g dm-3 amount per unit volume : mol m-3 or mol dm-3 N.B.: 1 dm3 = 1000 cm3 The amount concentration equation given above can be manipulated to give another useful equation : This equation must be used when dealing with volumes and solutions and must not be confused with another equation giving the amount of substance : back to top Concentration of Solutions - Calculations (1) Question : Sulphuric acid of concentration 0.1 mol dm-3 reacts exactly with 10 cm3 of 0.2 mol dm-3 sodium carbonate(aq). What volume of sulphuric acid is needed? Answer : The amount of sodium carbonate = amount concentration x volume = 0.2 mol dm-3 x (10 cm3/1000) dm3 = 0.2 mol dm-3 x 0.01 dm3 = 0.002 mol balanced chemical equation : H2SO4(aq) + Na2CO3(aq)Na2SO4(aq)...
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