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Chemistry 'Moles' Investigation  

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Leanne Haines 11B Chemistry 'Moles' Investigation Calcium Carbonate + Hydrochloric acid ? Calcium Chloride + Carbon Dioxide + Water CaCO + 2HCl ? CaCl + CO + H O Input Variables Outcome Mass of calcium carbonate Amount of carbon dioxide Concentration of HCl Amount of carbon dioxide In the experiment the mass of calcium carbonate will be changed. The concentration of HCl will be kept constant. We will need to do a moles calculation to workout a suitable amount of HCl to be used. The HCl needs to be in excess to make sure that all the Calcium Carbonate will react with it. By doing a mole calculation we can find the exact amount of HCl that will react with the calcium carbonate. This will be done in the preliminary work. The solution of HCl is 1M. Apparatus Conical flask Clamp and clamp stand HCl Calcium carbonate Scales Delivery tube Small test tube (with string attached to it) Measuring Cylinder (leave space 4 pic) Method First of all the Calcium Carbonate is...

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