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ADVANCING PHYSICS - COURSEWORK 3 MAKING SENSE OF DATA Introduction Through this task I am going to investigate the relationship between the voltage and efficiency of the light bulb's light emitting capacity. Efficiency is defined as useful energy output divided by the total electrical power consumed (a fractional expression).It is a dimensionless number with a value between 1 and 0, or when multiplied by 100 given a percentage. Efficiency = Power out put / Power input When lighting a light bulb, the electrical energy input is converted in to both light and heat energies. Here we are measuring the efficiency of the light bulb, i.e. the % of the electrical input energy that's converted in to the light energy. Experiment The light energy emitted can be done by running various voltages through a circuit containing a light bulb and ammeter. The light bulb will be immersed upside down in a beaker containing water .Care was given, so...

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