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This is a portion of the main project taken from between. Case of Doubled screen(diagram only) First max. First Max. GENERALIZATION FOR N - SCREENS. First of all let us consider a simple case in which we find the fringe width on nth screen of first maxima. The diagram may be S1 S2 S3 S4 N => odd ? ................... ................... .................... .................. .................... ..................... D D D D Again if n is odd then we would obtain the fringe width d/2 & thus the separation between two maximas = d. Therefore, if n is odd then fringe width of first maxima = d /2. And if n is even, then we would get fringe width greater then that when n is odd and it would be ?D/d. Note: Here we are considering diagram type A, ie n=>odd suppose we considered B, then also we would get same result. THIS IS A VERY GENERAL CASE IN WHICH WE CAN CALCULATE " FRINGE WIDTH" FOR ANY SCREEN NUMBER .THE MAIN PART OF THIS IS THAT WE...

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